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The Op-Amp Monostable Multivibrator (One-Shot) An extension of the astable multivibrator is the one-shot, or monostable multivibrator One-shots are available in integrated circuit form but can also be constructed from more general-purpose op-amps In this section, we rst look at the op-amp one-shot, taking special note of the analogy with the astable multivibrator Figure 1557 depicts an op-amp monostable multivibrator Its operation is summarized in the associated timing diagram, showing that if a negative voltage pulse is applied at the input, vin , the output of the op-amp will switch from a stable state, +Vsat , to the unstable state, Vsat , for a period of time T , which is determined by a charging time constant, after which the output will resume its stable value, +Vsat In the analysis of the one-shot circuit, it will be assumed that the diode is an offset diode, with offset voltage Voff , and that vout = +Vsat for t < t0 For t < t0 , before the negative input pulse is applied, the input terminal voltages are given by R2 v = Vsat R2 + R 3

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1. Open Windows Explorer and create a new folder on your C:\ called Share. Then make this folder into a new network share, as shown in the Creating a Network Share section of this chapter. 2. Create a new project and choose the Console application template. Name your application TestLabSetup and place it on the C:\ drive as well. 3. Delete the code files and create a new class in your project called SetUp. VB .NET will add a file called Module1.vb, while C# will add a file called Program.cs. While there is nothing wrong with these files, let s start from scratch so that both the VB .NET and C# examples will be very similar. 4. Remove any code that Visual Studio adds to the SetUp class. 5. With the SetUp class now empty, create the following methods and any Imports/using statements, as shown here: VB .NET Imports System.Text.RegularExpressions Public Class SetUp Shared Sub Main(ByVal args() As String) End Sub

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Provided that v + > v , the op-amp will remain in its positive saturated state, then, until some external condition causes = v + v to become negative This condition is brought about at t = t0 by the trigger pulse vin , which brie y lowers the noninverting-terminal voltage by V volts If V is suf ciently large, the following condition will be satis ed: R2 v + = Vsat V < V R2 + R 3 (1550)

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and the op-amp will switch to the negative saturation state, as indicated in Figure 1557 The noninverting-terminal voltage may be expressed as a function of time for t > t0 , considering that vout has switched to Vsat at t = t0 and the diode now acts as an open circuit, since v is negative With the diode out of the picture, then, the R1 C circuit will discharge, causing v to drop from its initial voltage (V ) toward Vsat The circuit of Figure 1558 depicts the equivalent switching circuit, illustrating that the capacitor discharges from the initial value of vC (t0 ) = V toward the nal value, Vsat Recalling the analysis of transients in 5, we know that the capacitor voltage is given by the expression vC (t) = [vC (t0 ) + Vsat ]e (t t0 )/R1 C Vsat (1551)

vC (t)

15

Public Shared Sub ShowHelp() End Sub Public Shared Function GetPCData(ByVal RunReport As String) As String End Function Public Shared Function CheckPCData(ByVal CheckReport As String) As String End Function Private Shared Function CheckForOS(ByVal ReportData As String) As Boolean End Function

As v becomes more negative, it eventually becomes smaller than v + Thus, when the condition vC (t) = [vC (0) + Vsat ]e (t t0 )/R1 C Vsat = v + (1552)

is met, the comparator will switch back to the positive saturation state, +Vsat , and remain in that state until a new trigger pulse is provided The value of the noninverting-terminal voltage during the time the output is in the negative saturated state is determined by the positive feedback circuit: v + = Vsat R2 R2 + R 3 (1553)

Clearly, the duration of the output pulse provided by the one-shot is determined by the time constant of the R1 C circuit, as well as by the value of the resistive voltage divider in the positive feedback network, as illustrated in Example 1514

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