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I would replace a string by another on the PDF, it's possible ? thank you verry mutch. ... a text from PDF, my problem was to replace a string by another, ... Please could you make a sample project for me available ( C# or VB. The Writeln procedure displays a string to your screen and then returns the cursor to the left margin of the following screen line This action is actually two distinct activities, and Writeln very economically uses a mechanism that already exists: the Write procedure The first thing that Writeln does is call Write to display the string itself to the screen Remember that the caller loaded the address of the string to be displayed into DX before calling Writeln Nothing has disturbed DX, so Writeln can immediately call Write, which will fetch the address from DX and display the string to the screen Returning the cursor is done by displaying the newline sequence, which is stored in a string named CRLF (If you recall, the carriage return and line feed character pair was built right into our message string in the EATASM program that we dissected in 8) Writeln again uses Write to display CRLF Once that is done, the work is finished, and Writeln executes a RET instruction to return execution to the caller Calling procedures from within procedures requires you to pay attention to one thing: stack space Remember that each procedure call pushes a return address onto the stack This return address is not removed from the stack until the RET instruction for that procedure executes If you execute another CALL instruction before returning from a procedure, the second CALL instruction pushes another return address onto the stack If you keep calling procedures from within procedures, one return address will pile up on the stack for each CALL until you start returning from all those nested procedures If you run out of stack space, your program will crash and return to DOS, possibly taking DOS with it This is why you should take care not to use more stack space than you have Ironically, in small programs written in real mode flat model, this usually isn't a problem Stack space isn't allocated in real mode flat model; instead the stack pointer points to the high end of the program's single segment, and the stack uses as much of the segment as it needs For small programs with only a little data (such as the toy programs we're building and dissecting in this book), 95 percent of the space in the segment has nothing much to do and can be used by the stack if the stack needs it (Which it doesn't not in this kind of programming!) Things are different when you move to real mode segmented model In that model, you have to explicitly allocate a stack segment of some specific size, and that is all the space that the stack has to work with So, ironically, in a program that can potentially make use of the full megabyte of real mode memory, it's much easier to foment a stack crash in segmented model than flat model So, when you allocate space for the stack in real mode segmented model, it makes abundant sense to allocate considerably more stack space than you think you might ever conceivably need EAT2ASM at most uses 4 bytes of stack space, because it nests procedure calls two deep (Writeln within itself calls Write) In a program like this, stack allocation isn't an issue, even if you migrated it to the segmented model Nonetheless, I recommend allocating 512 bytes of stack to get you in the habit of not being stingy with stack space Obviously, you won't always be able to keep a 128-to-1 ratio of need-to-have, but consider 512 bytes a minimum for stack space allocation in any reasonable program that uses the stack at all (We allocated only 64 bytes of stack in EATSEGASM simply to show you what stack allocation was The program does not, in fact, make any use of the stack at all) If you need more, allocate it Don't forget that there is only one stack in the system, and while your program is running, DOS and the BIOS and any active memory resident programs may well be using the same stack If they fill it, you'll go down with the system so leave room!. find and replace text in pdf using itextsharp c#: Replacing text in PDF file using iTextSharp - Alex Joh's Blog itextsharp replace text in pdf c# How to replace specific word in pdf using itextsharp C# .net ...
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Here's a new machine instruction: CALL The label Writeln refers to a procedure As you might have athered (especially if you've programmed in an older language such as Basic or FORTRAN), CALL Writeln simply tells the CPU to go off and execute a procedure named Writeln The means by which CALL operates may sound familiar: CALL first pushes the address of the next instruction after itself onto the stack Then CALL transfers execution to the address represented by the name of the procedure The instructions contained in the procedure execute Finally, the procedure is terminated by CALL's alter ego: RET (for RETurn) The RET instruction pops the address off the top of the stack and transfers execution to that address Since the address pushed was the address of the first instruction after the CALL instruction, execution continues as though CALL had not changed the flow of instruction execution at all See Figure 91.Related: QR Code Generation Java , VB.NET QR Code Generation Image, QR Code Generating Word Size NET UPC-E : For drawing and printing dynamic 1d barcode . 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How to Link EAN-13 Barcode to Cell Contents. .Related: .NET Winforms Barcode Generation , Barcode Generator SSRS Library, ASP.NET Barcode Generation You'll find yourself writing sequences like this a lot, when a single test decides between one of two courses of action One course here is to load the value 5 into AL, and the other course is to load 4 into AL Notice that after the appropriate MOV instruction is executed, a RET takes care of passing execution back to the caller If DispID were not a procedure, but simply a sequence coded into the main line of instructions, you would need an unconditional jump (JMP) after each MOV to continue on with instruction execution somewhere else in the program Using RET is much neater-which is yet another reason to wrap up small tasks such as display adapter identification in a procedure wrapper Finally if neither PS/2 nor EGA are present, DispID realizes that, by default, one of the original generation of display boards is on the bus Telling MDA from CGA is not done with a BIOS call at all, because the first generation BIOS did not know which display board was present (That was a feature instituted with the EGA in 1984) Instead, there is a separate software interrupt, 11H, that returns machine configuration information. 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