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I ve been using the trace statement since the beginning of the book, and it s pretty clear how it works by now. But stop and realize for a moment: you ve been doing string manipulation this whole time! Not only have you been converting objects to strings and writing string literals, you ve been constructing complex strings out of multiple substrings all within the parentheses of trace(). In this book, you ll usually see the arguments to trace() combined with the + operator as just described. However, you can also pass as many string arguments as you like to trace(), and it will concatenate them automatically, separated by spaces.



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g4 (mod p ) , . . .

(18.17)

var a:String = "Ground control"; var b:String = "Major Tom"; trace(a, "to", b); //Ground control to Major Tom

To convert a string to the same text in capital letters, simply call the toUpperCase() method. As shown in the following example, this returns a new string object with the same letters switched to uppercase. The other nonletter characters are not affected.

until we find g (mod p ) . As mentioned above, this method of solving the ' discretc log problem is essentially the analog of trial division for factoring. For example, suppose we are given g = 3 , p = 101, and we want to find the exponent a such that g a (mod p ) = 94. Then we would compute

var cleanser:String = "Ajax"; var webTechnology:String = cleanser.toUpperCase(); trace(webTechnology); //AJAX

To switch to all lowercase, use toLowerCase() instead:





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32 (mod 101) = 9 3'3 (rrlod 101) = 27

(18.18)

var loudText:String = "CAN YOU HEAR ME " var quietText:String = loudText.toLowerCase(); trace(quietText); //can you hear me

Calling these methods does not change the case of the string but returns a new string with the case change. The original string stays the same. If you want to change the original, you have to set its value to the result of the function. For example:

34 (rriod 101) = 81 (rnod 101) = 41

Using toUpperCase() or toLowerCase() can be helpful when you need to make sure that two strings are compared without regard to case, as when checking a password:

var inputPW:String = "HaXoR" var storedPW:String = "haxor"; if (storedPW.toLowerCase() == inputPW.toLowerCase()) { trace("Login successful"); } else { trace("Login error"); } //Login successful

3" (rriod 101)= 94.

Because the optimal p equals 1, any parallel two lines have to satisfy the following condition: 1 p p (18.19)

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When you work with strings, you may need to access a speci c character in the string or know the total number of characters in the string. You might nd it helpful to think of a string as an array of single characters. (C strings are exactly this.) Although a string in ActionScript is not an array, it has some array-like properties. A string has indices starting with 0 and counting up, each containing a single character. You can learn more about arrays in 8, Arrays. The following section describes ways to access the speci c characters within a string.

ActionScript 3.0 has no special class or type for single characters, like in some other languages. Although I may refer to characters, these are always stored in String instances of length 1.

Alternatively, we could bcgiri at yk (mod p ) , for any given k . In any case. the cxpected number of multiplications is about p / 2 .

To determine the number of characters a string object contains, you can check its length property. This property works just like an array s length property.

The baby-step giant-step algorithm provides an improvement over trial multiplication based on a time-memory trade-off [99]. Again, we are given a generator g, a prime p and x = ga (mod p ) , and we want to determine a. First, we selectm= T h e n w e h a v e a = i m + j f o r s o m e i E {0,1,. . . , m-1} and j E {0,1,.. . ,m - l}. For this choice of i and j , it follows that

var bigWord:String = "PNEUMONOULTRAMICROSCOPICSILICOVOLCANOCONIOSIS"; trace("Number of letters: ", bigWord.length); //45

A normal distance between any two lines is selected from among two distances d1 and d2 : dnorm = max d1 d2 where d1 = d2 = a1 xm + b1 ym + c1

length is a read-only property, which means that you cannot change its value explicitly unless you add more characters to your string.

[JX].

Unlike an array, you cannot access characters in a string using square bracket syntax:

var firstName:String = "Adair"; trace(firstName[1]);

g j = xg-ZnL (mod p )

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