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the declarator is n, which is a direct-declarator that consists only of a declarator-id, so by implication, n has type int If a declarator has one of the other possible forms, then you can determine the type of the identifier as follows: First, let T be the type implied by the decl-specifiers, ignoring non- type properties such as friend or static, and let D be the declarator Then repeat the following steps until you have reduced D to a declarator-id, at which point T is the type you seek: 1 If D has the form (D1), then replace D with D1 2 If D has the form * D1 or * const D1, replace T with "pointer to T" or "constant pointer to T" (not "pointer to constant T"), depending on whether the const is present Then replace D with D1 3 If D has the form D1 (parameter-declaration-list), replace T with "function returning T" with arguments as



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class InstanceMethodCall { private native void nativeMethod(); private void callback() { Systemoutprintln("In Java"); } public static void main(String args[]) { InstanceMethodCall c = new InstanceMethodCall(); cnativeMethod(); } static { SystemloadLibrary("InstanceMethodCall"); } }

defined by the parameter-declaration-list, and replace D with D1 4 If D has the form D1 [constant-expression], then replace T with "array of T" that has the number of elements given by the constant-expression, and replace D with D1 5 Finally, if the declarator has the form & D1, then replace T with "reference to T" and D with D1 As an example, consider the declaration

int *f();

Correct Menu Items Items that do not require a selection Items that apply to the entire window Items that operate on the object under the pointer Items that do not require a selection

Here is the implementation of the native method:





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We start with T and D being int and *f(), so D has the form *D1, where D1 is f() You might think that D could have either of the forms D1() or *D1 However, if D had form D1(), then D1 would have to be *f, and D1 would also have to be a direct-declarator (because the grammar at the beginning of this section allows only a direct-declarator to precede ()) If we look at the definition of direct-declarator, however, we see that it cannot contain a * Therefore, D can only be *f(), which has the form *D1, where D is f() Now that we have determined that D1 is f(), we know that we must replace T with "pointer to T, " which is "pointer to int, " and replace D with f() We have not yet reduced D to a declarator-id, so we must repeat the process This time, D1 can only be f, so we replace T with "function returning T," which is "function returning pointer to int with no arguments," and we replace D with f At this point we have reduced D to a declarator-id, so we're done We have determined that the declaration

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int *f();

declares f to have type "function with no arguments returning pointer to int " As another example, the declaration

Items that can operate each object in the selection (an intersection, not a union) Items that do not require a selection Items that apply to the entire window

JNIEXPORT void JNICALL Java_InstanceMethodCall_nativeMethod(JNIEnv *env, jobject obj) { jclass cls = (*env)->GetObjectClass(env, obj); jmethodID mid = (*env)->GetMethodID(env, cls, "callback", "()V"); if (mid == NULL) { return; /* method not found */ } printf("In C\n"); (*env)->CallVoidMethod(env, obj, mid); }

int* p, q;

has two declarators, *p and q For each declarator, T is int For the first declarator, D is *p, so we transform T to "pointer to int," and D to p The declaration, therefore, gives p the type "pointer to int" We analyze the second declarator independently, with T again being int and D being q At this point it should be obvious that the declaration gives q the type int Finally, let's analyze the arcane example from 1012/173:

double (*get_analysis_ptr())(const vector<Student_info>&);

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