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As you can see, January 29 plus a month causes problems for 1997, which is not a leap year. If you change 1997-01-29 to 1997-01-28 on the second line, there is no longer a problem. 7. Investigate the difference between the date formats WW and IW (week number and ISO week number) using an arbitrary date, and explain your findings. Solution 5-7. SQL> 1 select date '2005-01-01' as input_date 2 , to_char(date '2005-01-01', 'ww') as ww 3 , to_char(date '2005-01-01', 'iw') as iw 4* from dual INPUT_DATE WW IW ----------- -- -01-JAN-2005 06 07 SQL> If you don t get different results, try different dates within the same week. The difference between WW and IW has to do with the different definitions of week numbers. The WW format starts week number 1 on January 1, regardless of which day of the week that is. The ISO standard uses different rules: an ISO week always starts on a Monday. The rules around the new year are as follows: if January 1 is a Friday, a Saturday, or a Sunday, the week belongs to the previous year; otherwise, the week fully belongs to the new year. Similar rules apply for the ISO year numbering. 8. Look at Listing 5-15, where we use the REGEXP_INSTR function to search for words. Rewrite this query using REGEXP_LIKE. Hint: You can use {n,} to express at least n times. Solution 5-8a. First Solution SQL> select comments 2 from history 3 where regexp_like(comments, '([^ ]+ ){8,}'); COMMENTS -----------------------------------------------------------Not a great trainer; let's try the sales department! Sales also turns out to be not a success... Hired as the new manager for the accounting department Junior sales rep -- has lots to learn... :-) SQL> You could make your solution more readable by using character classes.



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static void Main() { int[] intArray = new int[] { 3, 4, 5, 6, 7, 9 }; Func<int, bool> myDel = new Func<int, bool>(IsOdd); // Delegate object var countOdd = intArray.Count(myDel); // Use delegate Console.WriteLine("Count of odd numbers: {0}", countOdd); } } This code produces the following output: Count of odd numbers: 4

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The previous example used a separate method and a delegate to attach the code to the operator. This required declaring the method, declaring the delegate object, and then passing the delegate object to the operator. This works fine and is exactly the right approach to take if either of the following conditions is true: If the method must be called from somewhere else in the program than just in the place it s used to initialize the delegate object If the code in the method body is more than just a statement or two long

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If neither of these conditions is true, however, you probably want to use a more compact and localized method of supplying the code to the operator, using a lambda expression as described in 15. We can modify the previous example to use a lambda expression by first deleting the IsOdd method entirely and placing the equivalent lambda expression directly at the declaration of the delegate object. The new code is shorter and cleaner and looks like this: class Program { static void Main() { int[] intArray = new int[] { 3, 4, 5, 6, 7, 9 }; Lambda expression var countOdd = intArray.Count( x => x % 2 == 1 ); Console.WriteLine("Count of odd numbers: {0}", countOdd); } } Like the previous example, this code produces the following output: Count of odd numbers: 4

@property (retain) NSString *fetchedData; @property (retain) NSString *processed; @property (retain) NSString *firstResult; @property (retain) NSString *secondResult; @property (assign) BOOL isWorking; - (IBAction)doWork:(id)sender; @end

We could also have used an anonymous method in place of the lambda expression, as shown following. This is more verbose, though, and since lambda expressions are equivalent semantically and are less verbose, there s little reason to use anonymous methods anymore. class Program { static void Main( ) { int[] intArray = new int[] { 3, 4, 5, 6, 7, 9 }; Anonymous method Func<int, bool> myDel = delegate(int x) { return x % 2 == 1; }; var countOdd = intArray.Count(myDel); Console.WriteLine("Count of odd numbers: {0}", countOdd); } }

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