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We provide conversion to all image formats supported by .NET framework via System.Drawing. Image class so you are able to export PDF files to BMP,JPG, PNG ... mod n (me)d mod n = m (ed mod But remember that we chose e and d such that ed -1 is exactly divisible (ie, with no remainder) by (p-1)(q1), or equivalently that ed is divisible by (p-1)(q-1) with a reminder of 1, and thus ed mod (p-1)(q-1) = 1 This gives us (me)d mod n = m 1mod n = m ie, that (me)d mod n = m This is the result we were hoping for! By first exponentiating to the power of e (ie, encrypting) and then exponentiating to the power of d (ie, decrypting), we obtain the original value, m Even more remarkable is the fact that if we first exponentiate to the power of d and then exponentiate to the power of e, ie, we reverse the order of encryption and decryption, performing the decryption operation first and then applying the encryption operation, we also obtain the original value, m! (The proof for this result follows the exact same reasoning as above) We will see shortly that this wonderful property of the RSA algorithm, (me)d mod n = m = (md)e mod n will be of great use The security of RSA relies on the fact that there are no known algorithms for quickly factoring a number, in this case the public value n, into the primes p and q If one knew p and q, then given the public value e, one convert pdf to image using ghostscript c# Convert a PDF into a series of images using C# and ... - Cyotek
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