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This metadata must be available both at compile time (to generate the IL code) and at run time (to create the RCW object) The metadata for a COM component is similar to the metadata associated with standard NET types, except for a few attributes that iden tify that type as a COM component In general, this metadata is extracted from the COM object s type library, implicitly if you use Visual StudioNET or explicitly if you use the TlbImp utility..

If you look at Figure 9-4, you can see that the key that must have just been pressed is the B key The A key was already pressed, as was the left Shift key You need to find a sequence of operations that can work this out This means that it is time to create another algorithm When faced with a situation like this, I think that it s a bit like being a detective A detective arrives at the scene of a crime, looks at the evidence, and then tries to build up a sequence of events that explains everything that has been found A programmer has some information that comes in from which he or she must produce the desired output by a process that he or she needs to devise.

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Figure 6-19. A SharePoint view can filter on any number of columns. As when sorting, you can set the drop-down lists to None.

If you have a problem like this, it s often useful to set out what you know and what you want to find out and then try to find a way of getting one from the other In this case, in the input side, you have a list of keys that were pressed before and a list of keys that are pressed now The output that you want is any keys that have been pressed since you last looked If you think about it for a while, you can come up with a way to tell which keys have just been pressed: Any keys in the list of keys that are pressed now that are not in the list of keys that were pressed before are ones that have just been pressed You can test this by applying it to the keys in Figure 9-4.

The sys.dm_db_partition_stats DMV returns page and row counts for every partition in the current database. One row is returned for each partition with information about the

In Active Directory, user accounts are defined as objects as are group and computer accounts. This means that user accounts have security descriptors that list the users and groups that are granted access. Security descriptors also define ownership of the object and specify the permissions that those users and groups have been assigned with respect to the object.

Both the A key and the left Shift key are in the oldKeys array and the pressedKeys array However, the B key is only in the pressedKeys array, so it must have just been pressed down At the moment, your solution does not give you any steps to follow; what you need to do now is convert it into a proper algorithm Initially, you can write this in English; then you can convert it into C# code Take each value in pressedKeys in turn and check to see if it occurs in oldKeys If you don t find the value in oldKeys, that key must have been pressed since you last looked You know that to work your way through an array, you need to use a for loop of some kind.

In the example that follows, I use this technique to create an extended TextBox control named TextBoxEx, with several additional properties that perform advanced validation chores. I chose this example because it s relatively simple without being a toy control and because it s complete and useful enough to be used in a real application. The TextBoxEx control has a property named IsRequired, which you set to True if the control must be filled before moving to another control, and the ValidateRegex prop erty, which is a regular expression that the field s contents must match. There s also an ErrorMessage property and a Validate method, which returns True or False and can dis play a message box if the validation failed. The control will take advantage of the Val idating event of the standard TextBox control to cancel the focus shift if the current value can t be validated.

Partitioning Fundamentals 508 Designing Partitions 512 Creating Partitions 513 Viewing Partition Information 519 Maintaining Partitions 526 Using Partitions 535 Partitioning Scenarios 536 Summary 539.

In this case, you need to put one for loop inside another because you need to look through the oldKeys array for each of the values in pressedKeys This is called nesting the for loops and is a very common programming technique:.

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