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WriteLine("result: {0} decimal: {1}", ConvertToBinary(result3), result3); // demonstrate the ~ operator ConsoleWriteLine("\n--- ~ Operator ---"); ConsoleWriteLine("binary: {0} decimal: {1}", ConvertToBinary(b1), b1); int result4 = (byte)~b1; ConsoleWriteLine("result: {0} decimal: {1}", ConvertToBinary(result4), result4); // wait for input before exiting ConsoleWriteLine("Press enter to finish"); ConsoleReadLine();.



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A helper class, called SampleRow, represents the data: using System; using System.Collections; using System.Collections.Generic; using System.ComponentModel; public class SampleRow { private string _name; private string _description; private int _id; [DataObjectField(true, true)] public int Id { get { return _id; } set { _id = value; } } [DataObjectField(false)] [DefaultValue("New row")] public string Name { get { return _name; } set { _name = value; } } [DataObjectField(false)] [DefaultValue("")] public string Description { get { return _description; } set { _description = value; } } public SampleRow() { _id = -1; } public SampleRow(int id, string name, string description) { _id = id; _name = name; _description = description; } }





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In diesem Artikel werden ich Ihnen 3 Top-OCR-Programme für Mac vorstellen und Ihnen der Nutzen jedes Produkt aufzeigen.

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} private static string ConvertToBinary(int value) { return String.Format("{0:00000000}", int.Parse(Convert.ToString(value, 2))); } } The statement in the ConvertToBinary method formats the binary string nicely; you can learn more about formatting in 16. Compiling and running the code in Listing 5-20 produces the following results; for each example, you can see the binary and decimal values and the result of the operator being applied: --- & Operator --binary: 10001010 decimal: 138 binary: 10000001 decimal: 129 result: 10000000 decimal: 128 --- | Operator --binary: 10001010 decimal: 138 binary: 10000001 decimal: 129 result: 10001011 decimal: 139 --- ^ Operator --binary: 10001010 decimal: 138 binary: 10000001 decimal: 129 result: 00001011 decimal: 11 --- ~ Operator --binary: 10001010 decimal: 138 result: 01110101 decimal: 117 Press enter to finish The left and right shift operators move all the bits in a value to the left or right by a specified number of places and inserting the same number of zeros to fill in the gaps. Listing 5-21 demonstrates the leftand right-shift operators. Listing 5-21. Left- and Right-Shifting a Byte Value using System; class Listing 21 { static void Main(string[] args) { byte b = 15; // left shift the byte two places int result = b << 2; // show the before and after values

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<wssp:Confidentiality wsp:Usage="wsp:Required" xmlns:wssp="http://schemas.xmlsoap.org/ws/2002/12/secext" /> <wssp:Confidentiality wsp:Usage="wsp:Optional" xmlns:wssp="http://schemas.xmlsoap.org/ws/2002/12/secext" />

Console.WriteLine("--- Left-shift Operator ---"); Console.WriteLine("Before: {0} ({1})", ConvertToBinary(b), b); Console.WriteLine("After: {0} ({1})", ConvertToBinary(result), result); b = 60; // right shift three places result = b >> 3; // show the before and after values Console.WriteLine("\n--- Right-shift Operator ---"); Console.WriteLine("Before: {0} ({1})", ConvertToBinary(b), b); Console.WriteLine("After: {0} ({1})", ConvertToBinary(result), result); // wait for input before exiting Console.WriteLine("Press enter to finish"); Console.ReadLine(); } private static string ConvertToBinary(int value) { return String.Format("{0:00000000}", int.Parse(Convert.ToString(value, 2))); } } The code in Listing 5-21 shifts a value two places to the left and shifts another value three places to the right. Compiling and running the code in Listing 5-21 produces the following results: --- Left-shift Operator --Before: 00001111 (15) After: 00111100 (60) --- Right-shift Operator --Before: 00111100 (60) After: 00000111 (7) Press enter to finish You can see that when I shift to the left, all of the 1s in the binary string are moved two places to the left. This has the effect of changing the value that is represented from 15 to 60 (see Figure 5-1 for details of why). Notice that two new zeros have been put in to the rightmost positions. When I shift three places to the right, the bits are moved in the opposite direction notice that one of the 1s is shifted out of the byte entirely. When this happens, the 1 value is gone for good; shifting back to the left doesn t restore it. Notice also that when a value is shifted out, it doesn t reappear on the other side (as though the values were in a loop); the positions are always filled with 0 values.

With one exception, the assignment operators allow you to conveniently apply one of the other operators and assign the result in a single step. Table 5-15 describes the assignment operators.

Assigns a value to a variable Adds to and assigns a value Subtracts from and assigns a value Multiplies and assigns a value Divides and assigns a value Remainder and assigns a variable Logical AND and assigns a variable Logical OR and assigns a variable Logical XOR and assigns a variable Left-shift and assigns a variable Right-shift and assigns a variable

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