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0 is a subnet of network 10000 14 B Route aggregation CIDR is a technology that implements route aggregation, but the question asks what the concept is called, and the concept is route aggregation 15 B 218 The key is to determine how many bits are available for subnetting We know we need 31 hosts, so we know we need at least 5 bits because 25 = 32 However, we lose 2 bits for each subnet for the subnet and broadcast address, so we actually need 6 bits for the hosts because using 5 bits would only give us 30 hosts per subnet Since there are 24 total available bits for subnets on network 10000/8, 24 6 host bits = 18 subnet bits, and 218 = 262,144 available subnets..



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For the transfer equilibrium between a solution and a solid phase of the electrolyte BA it holds that A G - T = RT in (%&)





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16 C 16,382 If there are four subnets, that means we have used 2 of the available host bits because 22 = 4 This leaves 16 2 = 14 bits for subnets, and 214 2 = 16,382 17 C 1015127255 Using a /17 means that we have used 1 bit for the subnet, leaving 7 bits in the third octet The all 1s means to set all of those bits to 1 and all the bits in the last octet to 1 This means that the last octet is 255 (8 bits set to 1) and the 3rd octet is 127 (highest bit is 27 = 128, so 255 128 = 127) 18 C subnet 1010100/16 This value cannot be used as a subnet address since the host portion is not all zeros.

\PBA(S)/

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The other network addresses given all have the host portion all zeros Any valid address can be used as a host address 19 B /20 for the first eight subnets, /24 for the remaining 13 Because nine subnets are needed, we need to use 4 bits of the host address in the third octet because 24 = 16 possible subnets (3 bits would only yield eight subnets) Then we need 13 more subnets, which means we need to take another 4 bits to give us 16 more possible subnets (24 = 16) This means we need 16 + 4 = /20 for the first eight subnets and 16 + 4 + 4 = /24 for the remaining 13 subnets 20 D /19 We need to determine how many bits are needed to support 4,387 hosts.

= 2RTln " ^ W m BA (s)r (s)

(3.2.41)

We know that using 8 bits gives us 255 hosts (all 1s for a single octet) If we double this by using an additional bit, that gives us 510 hosts; double again gives 1,020; double again gives us 2,040; double again gives us 4,080; and double again gives us 8,160 We had to double five times to get the desired number of hosts, which means we had to take 5 bits + original 8 bits = 13 total bits for hosts from the available 16 (/16 was the original network) This leaves 3 bits left for subnetting (16 13 = 3), so /16 + 3 bits = /19 subnet mask..

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where the P B A' S a r e the solubility products, the mBA's the solubilities and y 's the mean activity coefficients in each of the two phases. As separation of the standard Gibbs transfer energy of the electrolyte as a whole into the individual contributions for the anion and the cation can, of

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course, not be carried out by a thermodynamic procedure, a suitable extrathermodynamic assumption must be selected. A suitable extrathermodynamic approach is based on structural considerations. The oldest assumption of this type was based on the properties of the rubidium(I) ion, which has a large radius but low deformability. V. A. Pleskov assumed that its solvation energy is the same in all solvents, so that the Galvani potential difference for the rubidium electrode (cf. Eq. 3.1.21) is a constant independent of the solvent. A further assumption was the independence of the standard Galvani potential of the ferricinium-ferrocene redox system (H. Strehlow) or the bis-diphenyl chromium(II)-bis-diphenyl chromium(I) redox system (A. Rusina and G. Gritzner) of the medium. While the validity of these assumptions has been criticized, that adopted by A. J. Parker has received the widest acceptance, i.e. that tetraphenylarsonium tetraphenylborate (Ph4AsPh4B),

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