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The steel in the cores is attracted to the permanent magnets in a direction that is perpendicular (normal) to the operating motor force. The magnetic flux density within the air gap of linear motors is typically several thousand gauss. A constant magnetic force is present whether or not the motor is energized. The normal force of the magnetic attraction can be up to ten times the continuous force rating of the motor. This flux rapidly diminishes to a few gauss as the measuring point is moved a few centimeters away from the magnets. Cogging is a form of magnetic detenting that occurs in both linear and rotary motors when the motor coil s steel laminations cross the alternating poles of the motor s magnets. Because it can occur in steel-core motors, manufacturers include features that minimize cogging. The high thrust forces attainable with steel-core linear motors permit them to accelerate and move heavy masses while maintaining stiffness during machining or process operations. The features of epoxy-core or ironless-core motors differ from those of the steel-core motors. For example, their coil assemblies are wound and encapsulated within epoxy to form a thin plate that is inserted in the air gap between the two permanent-magnet strips fastened inside the magnet assembly, as shown in Figure 1-29. Because the coil assemblies do not contain steel cores, epoxy-core motors are lighter than steel-core motors and less subject to cogging. The strip magnets are separated to form the air gap into which the coil assembly is inserted. This design maximizes the generated thrust force and also provides a flux return path for the magnetic circuit. Con-



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Sample Javascript code to use PDFTron SDK's built-in rasterizer to render PDF images on the fly and save the resulting images in various raster image formats ...

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An RC transient identical to that in Problems 7.1 and 7.2 has a power transient pR 360e t=0:00001 Obtain the initial charge Q0 , if R 10

OPTIONS Supported Header Fields When Used with Response 484 Sending to UA or Proxy O O M Receiving from UA or Proxy M O M

Q2 =2C, 0

The switch in the RL circuit shown in Fig. 7-21 is moved from position 1 to position 2 at t 0. Obtain vR and vL with polarities as indicated.

1

Fig. 7-21 The constant-current source drives a current through the inductance in the same direction as that of the transient current i. Then, for t > 0, i I0 e Rt=L 2e 25t vR Ri 200e

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25t

25t





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Figure 1-29 A linear ironless servomotor consists of an ironless magnetic way and an ironless coil assembly.

50t

OPTIONS Supported Header Fields When Used with All Other Responses Sending to UA or Proxy M O O O O M M M O M O Receiving from UA or Proxy M O M M M M M M M M M Insertion of dates in requests and responses Use

Negative power for the inductance is consistent with the fact that energy is leaving the element. this energy is being transferred to the resistance, pR is positive.

CHAP. 7]

and C 20 mF has a constant-voltage source of 100 V applied at t 0; there is no initial charge on the capacitor. Obtain i, vR , vC , and q, for t > 0.

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sequently, very little magnetic flux exists outside the motor, thus minimizing residual magnetic attraction. Epoxy-core motors provide exceptionally smooth motion, making them suitable for applications requiring very low bearing friction and high acceleration of light loads. They also permit constant velocity to be maintained, even at very low speeds. Linear servomotors can achieve accuracies of 0.1 m. Normal accelerations are 2 to 3 g, but some motors can reach 15 g. Velocities are limited by the encoder data rate and the amplifier voltage. Normal peak velocities are from 0.04 in./s (1 mm/s) to about 6.6 ft/s (2 m/s), but the velocity of some models can exceed 26 ft/s (8 m/s). Ironless linear motors can have continuous force ratings from about 5 to 55 lbf (22 to 245 N) and peak force ratings from about 25 to 180 lbf (110 to 800 N). By contrast, iron-core linear motors are available with continuous force ratings of about 30 to 1100 lbf (130 to 4900 N) and peak force ratings of about 60 to 1800 lbf (270 to 8000 N).

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The capacitor charge, and hence vC , must be continuous at t 0: vC 0 vC 0 0 As t ! 1, vC ! 100 V, the applied voltage. from Section 6.10, The time constant of the circuit is RC 10 1 s. Hence,

vC vC 0 vC 1 e t= vC 1 100e 10t 100 V The other functions follow from this. enters, vR vC 100 V, and so If the element voltages are both positive where the current

The switch in the circuit shown in Fig. 7-22(a) is closed at t 0, at which moment the capacitor has charge Q0 500 mC, with the polarity indicated. Obtain i and q, for t > 0, and sketch the graph of q.

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How to convert PDF to image in JavaScript using Cloud API (low ...
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