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Table 3-2. Method Summary of the FacesEvent Base Class*

1 2 3 4 5 6 7 8 9

CREATE OR REPLACE TYPE ProductNestedTable AS TABLE OF VARCHAR2(10);



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The thing to notice about this program is the way you dereference board in the loop: printf(" board: %c\n", *(*board + i)); As you can see, you use the expression *(*board + i) to get the value of an array element. The expression between the parentheses, *board + i, produces the address of the element in the array that is at offset i. Dereferencing this results in the value at this address. It s important that the brackets are included. Leaving them out would give you the value pointed to by board (i.e., the value stored in the location referenced by the address stored in board) with the value of i added to this value. So if i had the value 2, you would simply output the value of the first element of the array plus 2. What you actually want to do, and what your expression does, is to add the value of i to the address contained in board, and then dereference this new address to obtain a value. To make this clearer, let s see what happens if you omit the parentheses in the example. Try changing the initial values for the array so that the characters go from '9' to '1'. If you leave out the brackets in the expression in the printf() call, so that it reads like this printf(" board: %c\n", **board + i); you should get output that looks something like this: board: board: board: board: board: board: board: board: board: 9 : ; < = > @ A





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Let s try rewriting the VARRAY code example from the previous section using nested tables. First, define the nested table by running the statement above in SQL*Plus. After that, you will need to redefine the proc_DeleteProducts stored procedure. Run the following statement next:

This output results because you re adding the value of i to the contents of the first element of the array, board. The characters you get come from the ASCII table, starting at '9' and continuing to 'A'. Also, if you us the expression **(board + i), this too will give erroneous results. In this case, **(board + 0) points to board[0][0], whereas **(board + 1) points to board[1][0], and **(board + 2) points to board[2][0]. If you use higher increments, you access memory locations outside the array, because there isn t a fourth element in the array of arrays.

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So now that you ve used the array name using pointer notation for referencing a two-dimensional array, let s use a variable that you ve declared as a pointer. As I ve already stated, this is where there s a significant difference. If you declare a pointer and assign the address of the array to it, then you can use that pointer to access the members of the array.

BEGIN FOR i IN 1..tblProduct.LAST LOOP DELETE FROM Products WHERE ID = tblProduct(i); END LOOP; END; The next thing you need to do is to create a new factory class for the nested table type you ve created. The following class will implement the IOracleArrayTypeFactory interface:

You can see this in action here: /* Program 7.9 Multidimensional arrays and pointers*/ #include <stdio.h> int main(void) { char board[3][3] = { {'1','2','3'}, {'4','5','6'}, {'7','8','9'} }; char *pboard = *board; /* A pointer to char */

Returns the source UIComponent instance that delivered this event Returns the identifier phaseId for which phase this event is going to be delivered Sets the PhaseId during which this event will be delivered Checks whether this listener is of a listener instance that this event supports Broadcasts this event to the specified listener Convenience method that queues this event for broadcast at the end of the current requestprocessing lifecycle phase

for(int i = 0; i < 9; i++) printf(" board: %c\n", *(pboard + i)); return 0; } Here, you get the same output as before: board: board: board: board: board: board: board: board: board: 1 2 3 4 5 6 7 8 9

[OracleCustomTypeMappingAttribute("EDZEHOO.PRODUCTNESTEDTABLE")]

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