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Plaintext L I T T L E T I M E S 0 M U C H T 0 K N 0 W Ciphertext N B S M q T 9 Z I Y D D X K Y N E W J K Z R

The equation of a hypersphere can be formulated considering the hypersphere centered at point x n with radius 2 = x p 2 , here p is any point lying on the sphere. However, we can express this using Equation (21.12) in terms of homogeneous points: x p = 1 2



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Flash Player makes it easy to react to rollovers or hovering. You can use rollovers to change the appearance of a display object as the mouse hovers over it to emphasize the fact that it s active. The SimpleButton class has this behavior built in. It switches between its upState, overState, and downState display objects automatically as the mouse leaves, enters, and depresses the button. You can easily add this behavior to any InteractiveObject by listening to the MouseEvent .ROLL_OVER and MouseEvent.ROLL_OUT events, as Example 21-4 shows.

EXAMPLE 21-4

11. Suppose that the same Enigma rotors (in the same order) and reflector are used as in Problem 10, and the stecker has no cables connected. Solve for the initial rotor settings and recover the plaintext given the following ciphertext.





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package { import flash.display.Sprite; public class ch21ex4 extends Sprite { public function ch21ex4() { var circ:ClickableCircle = new ClickableCircle(); circ.x = circ.y = 100; addChild(circ); } } } import flash.display.Sprite; import flash.events.MouseEvent; class ClickableCircle extends Sprite { public function ClickableCircle(color:uint = 0, size:Number = 50) { graphics.beginFill(color, 0.25); graphics.drawCircle(0, 0, size); graphics.endFill(); addEventListener(MouseEvent.ROLL_OVER, onRollOver); addEventListener(MouseEvent.ROLL_OUT, onRollOut); onRollOut(null); //start in the "up"/not hovered state. } protected function onRollOver(event:MouseEvent):void { alpha = 1; } protected function onRollOut(event:MouseEvent):void { alpha = 0.5; } }

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Two sets of events deal with hovering: MOUSE_OVER, MOUSE_OUT, ROLL_OVER, and ROLL_OUT. The difference between these is subtle. The ROLL_OVER and ROLL_OUT events apply to a display object and its children, but the MOUSE_OVER and MOUSE_OUT events only apply to the display object. When moving your mouse from an inner display object to an outer display object, MOUSE_OUT is dispatched on the inner object as MOUSE_OVER is dispatched on the outer object. The difference might not be noticeable, however, because these events bubble, and the MOUSE_OUT event is followed up closely by a MOUSE_OVER event, although their targets are different. In Example 21-5, you cancel bubbling to see just how the events differ. You ll notice that when you use MOUSE_OVER and MOUSE_OUT, as the blue circles on the right do, only the one speci c display object under the mouse receives events, so the parent circle s stroke disappears when you mouse onto its child. It s best experimented with interactively, so run the example if you have a chance.

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(21.14)

EXAMPLE 21-5

package { import flash.display.Sprite; import flash.events.MouseEvent; public class ch21ex5 extends Sprite { public function ch21ex5() { //use ROLL_OVER and ROLL_OUT on the left (red) var a:NestedCircles = new NestedCircles(true, 0xff0000); //use MOUSE_OVER and MOUSE_OUT on the right (blue) var b:NestedCircles = new NestedCircles(false, 0x0000ff); a.x = 100; b.x = 250; a.y = b.y = 150; addChild(a); addChild(b); } } } import flash.display.*; import flash.events.MouseEvent; class NestedCircles extends Sprite { public var child:NestedCircles; protected var stroke:Shape; public function NestedCircles(useRoll:Boolean, color:uint = 0, size:Number = 60, isChild:Boolean = false) { graphics.beginFill(color, 0.25); graphics.drawCircle(0, 0, size); graphics.endFill(); stroke = new Shape(); addChild(stroke); stroke.graphics.lineStyle(5, 0xffff00); stroke.graphics.drawCircle(0, 0, size); stroke.visible = false; if (useRoll) { addEventListener(MouseEvent.ROLL_OVER, handler); addEventListener(MouseEvent.ROLL_OUT, handler); } else { addEventListener(MouseEvent.MOUSE_OVER, handler); addEventListener(MouseEvent.MOUSE_OUT, handler); } if (!isChild) { child = new NestedCircles(useRoll, color, size/2, true); addChild(child); child.y = -size; } } protected function handler(event:MouseEvent):void { switch (event.type) {

12. Develop a ciphertext only attack on the Enigma, assuming that all you know about the plaintext is that it is English. Analyze the work factor of your proposed attack and also estimate the minimum amount of ciphertext necessary for your attack to succeed. Assume that Enigma rotors, the rotor order, the movable ring positions, and the reflector are all known. Then you need to solve for the initial settings of the three rotors and the stecker. Hint: Since E is the most common letter in English, guess that the plaintext is EEEEEE.. . and use this noisy plaintext to solve for the rotor and stecker settings.

EXAMPLE 21-5

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